Have a question about using WolframAlpha?Answer (1 of 6) I hope this helps corresponding elements are equal 2x − y = 10 3x y = 5 (1) Solving equations Adding (1) & (2) (2x – y) (3x y) = 10 5 2x – y 3x y = 15 2x 3x – y y = 15 5x 0 = 15 x = 15/5 x = 3 Putting value of x in (1) 2x – y = 10 2(3) – y = 10 6 – y = 10 –y = 10 – 6 –y = 4 y = –4 Hence, x = 3 & y = –4
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Multiply − 1 1 by − 1 1 Add − 1 1 and 1 1 Substitute the values of a a, d d, and e e into the vertex form a ( x d) 2 e a ( x d) 2 e Set y y equal to the new right side Use the vertex form, y = a ( x − h) 2 k y = a ( x h) 2 k, to determine the values of a a, h h, and k kFactor 2x^2x1 2x2 x − 1 2 x 2 x 1 For a polynomial of the form ax2 bx c a x 2 b x c, rewrite the middle term as a sum of two terms whose product is a⋅c = 2⋅−1 = −2 a ⋅ c = 2 ⋅ 1 = 2 and whose sum is b = 1 b = 1 Tap for more steps Multiply by 1 1 2 x 2 1 x − 1 2 x 2 1 x 1 Rewrite 1 1 as − 1 1Simple and best practice solution for 2(x1)x(2x^21)= equation Check how easy it is, and learn it for the future Our solution is simple, and easy to understand, so don`t hesitate to use it as a solution of your homework If it's not what You are looking for type in the equation solver your own equation and let us solve it
So,the 'y' in the question,arcsin(2x/1x^2) is a little difficult to handle,so a smart substitution has been done in the form of x=tan θ which simplifies the 'y' to be equal to 2 arctan(x) Now,y=2tan^1(x) Differentiating both sides,we get dy/dx=2*1/1x^2 as derivative of tan^1(x) is 1/1x^2 And dy/dx is what was asked in the question Cheers ) 133K views View upvotes 9 2 Related Ex 75, 6 Integrate the function (1 − 𝑥2)/(𝑥(1 − 2𝑥)) ∫1 (1 − 𝑥2)/(𝑥(1 − 2𝑥)) 𝑑𝑥= ∫1 (1 − 𝑥^2)/(𝑥 − 2𝑥^2 ) 𝑑𝑥Factor x^{2}2x1 In general, when x^{2}bxc is a perfect square, it can always be factored as \left(x\frac{b}{2}\right)^{2} \sqrt{\left(x1\right)^{2}}=\sqrt{2} Take the square root of both sides of the equation x1=\sqrt{2} x1=\sqrt{2} Simplify x=\sqrt{2}1 x=\sqrt{2}1 Subtract 1 from both sides of the equation x ^ 2 2x 1 = 0 Quadratic equations such as this one can be solved
Differentiate the following wrt x cot1(4x2x23x2) Maharashtra State Board HSC Arts 12th Board Exam Question Papers 167 Textbook Solutions MCQ Online Tests 70Cos(x^2) (x−3)(x3) Zooming and Recentering To zoom, use the zoom slider To the left zooms in, to the right zooms out When you let go of the slider it goes back to the middle so you can zoom more You can clickanddrag to move the graph around If you just clickandrelease (without moving), then the spot you clicked on willGiven y = 2x(x 2 – 1) 5, show that (a) dy/dx = g(x)(x 2 – 1) 4 where g(x) is a function to be determined dy/dx= (2)(x 2 – 1) 5 (2x)*5(x 2 – 1) 4 (2x) dy/dx= (x 2 – 1) 4 ( 2(x 2 – 1) x 2 ) g(x) = 2(x 2 – 1) x 2 (b) Hence find the set of values of x for which dy/dx > 0 (x 2 – 1) 4 ( 2(x 2 – 1) x 2 ) = 0 2(x 2
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1 < x < 1 ← Prev Question Next Question → 1 vote 130k views asked in Mathematics by Afreen (307k points) Solve for x tan1 (2x/1x 2) cot1 (1x 2 /2x) = π/3;Piece of cake Unlock StepbyStep plot x^2y^2x Natural Language Math InputAnswer (1 of 12) Notice, \frac{x1}{2x1}\frac{2x1}{x1}=2 \frac{(x1)^2(2x1)^2}{(x1)(2x1)}=2 x^22x14x^24x1=2(x1)(2x1) 5x^22x2=4x^22x2 x^24x4=0
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API & Developer Solutions;Simple and best practice solution for x=(2x12*11)*x1 equation Check how easy it is, and learn it for the future Our solution is simple, and easy to understand, so don`t hesitate to use it as a solution of your homework If it's not what You are looking for type in the equation solver your own equation and let us solve it1/2yx5/2=0;y2x3=0 No solution System of Linear Equations entered 1 1/2yx5/2=0 2 y2x3=0 Equations Simplified or Rearranged 1 y/2 x = 5/2 2 y 2x =
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Contact Pro Premium Expert Support » Give us your feedback » Pro;Set the factor ' (1 2x)' equal to zero and attempt to solve Simplifying 1 2x = 0 Solving 1 2x = 0 Move all terms containing x to the left, all other terms to the right Add '1' to each side of the equation 1 1 2x = 0 1 Combine like terms 1 1 = 0 0 2x = 0 1 2x = 0 1 Combine like terms 0 1 = 1 2x = 1Solve for x 1/2x1/2x=x1 Simplify Tap for more steps Simplify each term Tap for more steps Combine and Combine and Simplify terms Tap for more steps Add and Cancel the common factor of Tap for more steps Cancel the common factor Rewrite the expression Move all terms containing to the left side of the equation Tap for more steps Subtract from both sides of the
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Subtract y2x=2 from yx=1 by subtracting like terms on each side of the equal signx2x=12 Add y to y Terms y and y cancel out, leaving an equation with only one variable that can be solved x=12 Add x to 2x x=1 Add 1 to 2 y2=2 Substitute 1 for x in y2x=2 Because the resulting equation contains only one variable, you can solve for y directly y=0 Add 2 toSet the factor '(3 2x)' equal to zero and attempt to solve Simplifying 3 2x = 0 Solving 3 2x = 0 Move all terms containing x to the left, all other terms to the right Add '3' to each side of the equation 3 3 2x = 0 3 Combine like terms 3 3 = 0 0 2x = 0 3 2x = 0 3 Combine like terms 0 3 = 3 2x = 3 Divide each side by '2' x = 15 Simplifying x = 15In order to differentiate this expression, you need to use the chain rule The chain rule gives f' (x) = uv' u'v The u and the v are two parts of the original function f (x) The apostrophe ' at the end means the derivative of that We need to assign values to u and v
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Simplify 1/2x^ (1/2) 1 2 x−1 2 1 2 x 1 2 Rewrite the expression using the negative exponent rule b−n = 1 bn b n = 1 b n 1 2 ⋅ 1 x1 2 1 2 ⋅ 1 x 1 2 Multiply 1 2 1 2 and 1 x1 2 1 x 1 2 1 2x1 2 1 2 x 1 2Answer (1 of 10) First you need to put it in the standard form of a quadratic equation which is ax^2 bx c = 0 2x^2 1 = 2(x 1)^2 2x^2 1 = 2(x^2 2x 1) 2x^2 1 = 2x^2 4x 2 1 = 4x 2 Since both 2x^2 are gone now it is just a simple equation 1 = 4x 2 3 = 4x x = 3/4Extended Keyboard Examples Upload Random Compute answers using Wolfram's breakthrough technology & knowledgebase, relied on by millions of students & professionals For math, science, nutrition, history, geography, engineering, mathematics, linguistics, sports, finance, music WolframAlpha brings expertlevel knowledge
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Weekly Subscription $249 USD per week until cancelled Monthly Subscription $799 USD per month until cancelled Annual Subscription $3499 USD per year until cancelledGraph f (x)=x^22x1 f (x) = x2 2x − 1 f ( x) = x 2 2 x 1 Find the properties of the given parabola Tap for more steps Rewrite the equation in vertex form Tap for more steps Complete the square for x 2 2 x − 1 x 2 2 x 1 Tap for more steps Use the form a x 2 b x c a x 2 b x c, to find the values of a a, b bOsculating circle y = 1/x^2 at x = 2;
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\int\frac{1}{x^2 1} \ dx I've tried the substitution method, u = x^2 1 Insights Blog I've tried the substitution method, u = x^2 1, du/dx = 2x But the x variable is still exist Also, the trigonometry substitution method, but the denominator is not in tex\sqrt{x^2 1}/tex form Thanks in advance Huygen Answers and Replies #2 tinytim Science Advisor1 < x < 1 inverse trigonometric functions; Example 3Show thatsin−1 (2x√(1−𝑥2)) = 2 sin1xSolving LHSsin−1 ( 2x √(1−𝑥2) )Putting x = sin θ = sin−1 ("2 sin θ " √(𝟏−𝒔𝒊𝒏𝟐" θ" )) = sin−1 ("2 sin θ " √(𝒄𝒐𝒔𝟐" θ" )) = sin−1 (2sin θ cos θ) = sin−1 (sin 2θ) (As 1 – sin2 θ = cos2 θ)(Using sin 2x = 2 sin x cos x)(Using
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X^ (1/2) WolframAlpha Area of a circle? Explanation lim x→∞ (1 2x)1 x = lim x→∞ eln(12x)1 x = e lim x→∞ln(12x) 1 x as exponential function is continous = eL L = lim x→∞ ln(1 2x)1 x = lim x→∞ 1 x ln(1 2x) = lim x→∞ ln(1 2x) x which is ∞ ∞ indeterminate so we can use L HopitalShare It On Facebook Twitter Email 1 Answer 2 votes answered
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Solve for x tan^1 (2x/1x^2) cot^1 (1x^2/2x) = π/3;Is y = 1/x a onetoone function?Expand (x1) (x2) (x3) (x4) \square!
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Polar plot r = 1/phi;Extended Keyboard Examples Upload Random Compute answers using Wolfram's breakthrough technology & knowledgebase, relied on by millions of students & professionals For math, science, nutrition, history, geography, engineering, mathematics, linguistics, sports, finance, music WolframAlpha brings expertlevel knowledgeWe can then substitute it into the formula y y 1 = m (x x 1 ) 1 Finding the gradient To find the gradient of the tangent, first find the gradient of the curve where x=1 y = 2x 2 x 1 > dy/dx = 4x 1 When x = 1, dy/dx= 4 (1)1 = 41 = 5 So the gradient of the required tangent is 5 2 Finding a point the tangent passes through We
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Volume of a cylinder?Rearrangement of this gives x^2 2x 3 = 0 Using quadratic equation theory, this then becomes (x 3)(x 1)=0 Any equation that equals zero must have another zero value on the other side of the equation Therefore when y is 0, x is either 3 or 1 Using these two x values, we can work out the y values from the original equations Using the simpler equation y=2x 2, if x is 3 thenThe four terms are 2 x, 1, x, and − 5 In the last step, we also distributed the 2 inside the parentheses on the right side Let's continue simplifying We see that both sides have a 2 x 2 term, so let's subtract 2 x 2 from each side Now let's finish isolating the x We'll add 5 to both sides of the equation, then divide by − 9
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If Y Sin 1 2x 1 X 2 Then Dy Dx Is Equal To
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As you have x2 then 1 x2 will always be positive So y is always positive As x becomes smaller and smaller then 1 1 x2 → 1 1 = 1 So lim x→0 1 1 x2 = 1 As x becomes bigger and bigger then 1 x2 becomes bigger so 1 1 x2 becomes smaller lim x→±∞ 1 1 x2 = 0 build a table of value for different values of x and calculate theEasy as pi (e) Unlock StepbyStep Natural Language Math Input3y=2x1 Geometric figure Straight Line Slope = 1333/00 = 0667 xintercept = 1/2 = yintercept = 1/3 = Rearrange Rearrange the equation by subtracting what is
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2xy=1 Geometric figure Straight Line Slope = 2 xintercept = 1/2 = yintercept = 1/1 = Rearrange Rearrange the equation by subtracting what is to the right of theHow would you differentiate f (x) = 2x (3x 1)^2 using the chain rule? Ex 62, 7 Show that 𝑦 = log(1 𝑥) – 2𝑥/(2 𝑥) , 𝑥 > – 1 , is an increasing function of 𝑥 throughout its domainGiven 𝑦 = log (1𝑥) – 2𝑥/(2 𝑥) , 𝑥 > –1We need to show that y is strictly increasing function for 𝑥 > –1 ie we need to show that (𝒅𝒚 )/𝒅𝒙 > 0 for 𝒙 > –1Finding 𝒅
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1
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1
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最も好ましい Y Sin 1 2x 1 X 2 If Y Sin 1 2x 1 X 2 Then Which Of The Following Is False Nyosspixmags
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Solved Y X 1 X 1 Y X 2 1 X 2 1 Y X 3 2x Chegg Com
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Solved 25 F X 1 Ifx So X 1 If X 0 26 F X Chegg Com
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If Y Cosec 1 2x 1 X 0 Lt X Lt 1 2 Then Find Dy Dx Brainly In
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Solved 3x 1 Find Dy Dx I 2 Find The Derivative Of Y With Chegg Com
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Solve X X 1 Dy Dx X 2 Y X3 2x 1 Maths Application Of Derivatives Meritnation Com